(3x^2+4x-20)/(x-4)

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Solution for (3x^2+4x-20)/(x-4) equation: 


D( x )

x-4 = 0

x-4 = 0

x-4 = 0

x-4 = 0 // + 4

x = 4

x in (-oo:4) U (4:+oo)

(3*x^2+4*x-20)/(x-4) = 0

3*x^2+4*x-20 = 0

3*x^2+4*x-20 = 0

DELTA = 4^2-(-20*3*4)

DELTA = 256

DELTA > 0

x = (256^(1/2)-4)/(2*3) or x = (-256^(1/2)-4)/(2*3)

x = 2 or x = -10/3

(x+10/3)*(x-2) = 0

((x+10/3)*(x-2))/(x-4) = 0

( x+10/3 )

x+10/3 = 0 // - 10/3

x = -10/3

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -10/3, 2 }

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